Shell Programming and Scripting

Hi,

does anybody knows how to manage, that the filenames are assigned to a variable in a loop afer getting them with set command in a ksh, like:

Code:

set B*.txt
i=1
c=$#
x=$((c+1))
echo "$x"
while [[ $x -gt i ]] ; do
_ftpfile$i="$"$i
echo "$_ftpfile$i"
i=$((i+1))
done

The first echo returns, that x = 4, and as long x is not gt. than i(=1), it should create a variable _ftpfile$i (_ftpfile1, _ftpfile2, _ftpfile3) with the value of the set command, means the filename in $i (which should be $1, $2 and $3).

here's the output:

4
awkb.ksh[13]: _ftpfile1=$1: not found
1
awkb.ksh[13]: _ftpfile2=$2: not found
2
awkb.ksh[13]: _ftpfile3=$3: not found
3

Thanks,
M

I think you should replace :

Code:

_ftpfile$i="$"$i

by

Code:

eval "_ftpfile$i=\$$i"

perfekt, thnx!