how to create csv file using shell script


 
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# 8  
Old 03-16-2010
Quote:
Originally Posted by rdcwayx
Code:
 awk -F "=" '/^Name/ {print ""; next} {printf "%s,", $2} ' */latest.txt

That will never print out the name associated with each record.

Also, splitting on "=" assumes that there will not be any equals signs in the value. It's probably a safe assumption but not necessarly a given (I have had to deal with data which treated the first occurrence of a character specially and any subsequent appearances literally). If there did happen to be another "=" the value of $2 would be truncated relative to the correct value.

Regards,
Alister
# 9  
Old 03-16-2010
Sorry fo rthe mistake, my first idea what something else, using eval :
Code:
for F in */latest.txt
do
    for ((i=0; i<5; i++))
    do
        read L
        eval $L
    done < $F
    echo "$Age,$Gender,$Name,$Street,$Occupation" >> outputfile
done

# 10  
Old 03-16-2010
Thanks to point that, just recognize the outputs are re-organized. The name part still need be exported to third part.

Here is the ugly code

Code:
awk -F "=" '{printf "%s,", $2} '  file* |sed s'/,,/\n/g' |awk -F "," '{print $2,$3,$1,$4,$5}' OFS=","


Last edited by rdcwayx; 03-16-2010 at 07:47 PM..
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