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How to execute commands read from another file?

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# 1  
Old 03-15-2010
Question How to execute commands read from another file?
Please help with this simple example. I can not figure out how to do it. A file named “job” contains only this one line:
Code:
var=5

I need a script to read the job file and execute it as a command. This is my attempt (it does not work):
Code:
#!/bin/sh
exec < job
echo "var = $var"

output should read “var = 5”

Thank you.
# 2  
Old 03-15-2010
Bug
Use the following shell script.It will be useful for your requirement.

Code:
 
var=10 
echo $var 
. job 
echo "var=$var"

job file contains

var=5
# 3  
Old 03-15-2010
rekha_sri,

I ran the code you suggested, but the script did not find the file "job" file
Code:
wolf-PC:~/computer_languages/UNIX/sp> ./exe_str
10
.: 4: job: not found

The "job" file and the "exe_str" script are both in the sp directory.

I appreciate you looking at this.
# 4  
Old 03-15-2010
rekha_siri probably meant:

Code:
var=10 
echo $var 
. ./job 
echo "var=$var"

If the directory containing the script called "job" is not in ${PATH} (or ${PATH} does not contain ".") the script will not be found even if your current working directory is that directory.
# 5  
Old 03-15-2010
Try this:

Code:
var=10 
echo $var 
source ./job 
echo "var=$var"

# 6  
Old 03-15-2010
MySQL
Thanks methyl, that workedSmilie
Code:
var=10 
echo $var 
. ./job 
echo "var=$var"

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