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break while loop in BASH

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# 1  
Old 03-13-2010
break while loop in BASH
Hi gurus, I have the following part of code which I am using for treating input
Code:
#!/bin/bash

while [[ $1 = -* ]]; do
    arg=$1; shift

    case $arg in
        -u)
            users="$1"
            shift
            ;;
        -g)
            groups="$1"
            shift
            ;;
        -m)
            mlength="$1"
            shift
            ;;
        -t)
            dfileg="$1"
            shift
            ;;
        --help)
            echo "-m maximum count of characters per line in group file"
            echo "for errors see file called: errorlog"
            break
            ;;
        *)
            break
            ;;

when I issue
Code:
./script -u john -g daemon -m 100 -t group

everything works fine

but when I issue
Code:
./script --help

the script echos text but did not exit. (I have to interrupt it by ctrl+c) how can I close script after issuing --help ? Thanks a lot
# 2  
Old 03-13-2010
Change 'break' to 'exit' in the --help case.
# 3  
Old 03-14-2010
Thanks a lot, this helps Smilie BTW is there any more elegant way of treating input ?
# 4  
Old 03-14-2010
Hi wakatana:

I don't think I would go so far as to call it elegant, but there is a standardized utility for dealing with command line options and arguments. getopts

It's usually implemented as a shell built-in, so search your shell's man page for 'getopts'.

Regards,
Alister
# 5  
Old 03-15-2010
yes, you should use getopts
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