Shell Programming and Scripting

OK I have a simple awk script:

Code:

$ awk '/03\/11\/10/' foofile|awk -f finderrors.awk

I want to use in the ksh script to so that I can do something like this:

Code:

#!/bin/ksh
TODAY=`date +"%D"`
awk /$TODAY/ foofile|awk -f finderrors.awk

The problem I am having is (I believe) is with the special characters in $TODAY, namely the forward slashes in the date.

I will eventually make it so the script will use today's date if no date argument is passed.

But for now I just want to use today's date. Is my only hope to edit the date and add the "\" in front of the "/"?

Thanks.

BTW: My first post here.. so forgive my newbie mistakes

try:

Code:

grep  "$TODAY" foofile|awk -f finderrors.awk

Just proof that I was stuck in a loop in my head trying to pass the date to awk!! thanks.

or pass the date to finderrors.awk and change the script to filter anything OTHER than the passed date.

Code:

#!/bin/ksh
TODAY=`date +"%D"`
awk -f finderrors.awk d="${TODAY}" foofile

finderrors.awk:

Code:

BEGIN {
  # whatever
}
$0 ~ d {
     # do the deed
}