[bash] command line substitution with environmental variables


 
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# 8  
Old 03-07-2010
bash dynamic variables

For future reference, this is an approximate
representation of the system so far. The method
suggested works and generates identical output
whilst processing.

I may have been overwhelmed with a working
system that I may have began to think a little
too far ahead with the possibilities when trying
to incorporate it into a function. However, I
still think it *might* be of some interest.

Code:
#!/bin/bash

declare -a FLAGS
FLAGS[0]="CFLAGS=\"-arch x86_64 -g -Os -pipe -no-cpp-precomp\""
FLAGS[1]="LDFLAGS=\"-arch x86_64 -bind_at_load\""

declare -a OPTION
OPTION[0]="./configure"
OPTION[1]="--bindir=/usr/local/bin"
OPTION[2]="--datarootdir=/usr/local/share"
OPTION[3]="--mandir=/usr/local/man"

declare -a CONFIG
declare do_flags=true

## check if array is not null
if [ -n "${FLAGS}" ]; then
## check if flags prefix ./configure
    if $do_flags
        then CONFIG=( "${FLAGS[@]}" )
        fi
        fi

## append options to array
CONFIG=( "${CONFIG[@]}" "${OPTION[@]}" )

## check contents of array
echo "${CONFIG[@]}"
## execute contents of array (disabled)
## eval "${CONFIG[@]}"

## check dynamic variables
eval "${FLAGS[@]}"
echo "CFLAGS=$CFLAGS"
echo "LDFLAGS=$LDFLAGS"

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