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Shell Programming and Scripting

Searching pattern and reformatting

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# 8  
Old 02-20-2010
Thanks Scottn..... the script worked on my system with /usr/xpg4/bin/awk
It would be really nice of you if you could please explain me the way this awk is working specially the 1 in the end, whats its purpose ?
# 9  
Old 02-20-2010
Quote:
Originally Posted by rochitsharma
Thanks Scottn..... the script worked on my system with /usr/xpg4/bin/awk
It would be really nice of you if you could please explain me the way this awk is working specially the 1 in the end, whats its purpose ?
Code:
/usr/xpg4/bin/awk '
  {for(I=1;I<=NF;I++) if ($I ~ /^[0-9]{10}$/) $1=$I FS $1}1' file

1 at the end of the code means the whole line, its also represented by $0.
code searchs for the 10 digits field by checking each field of each line of the file. If 10 digits of field is found then first column is rearranged with this part
Code:
$1=$I FS $1

namely it (10 digits field) is placed before first field as you wanted.

regards
# 10  
Old 02-21-2010
Thanks EAGLC
# 11  
Old 02-22-2010
Try:

Code:
sed  's/\(.*\)\([0-9]\{10\}\)\(.*\)/\2 &/' < file
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