Now that I have found with Locate, how to copy?


 
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Top Forums Shell Programming and Scripting Now that I have found with Locate, how to copy?
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Old 02-19-2010
> The problem is that the shell isn't even looking at
> the output of your first command. The shell's fd
> for stdout is simply being copied into the
> subprocess that is running find/aptitude/etc. and
> that is outputing directly to your console.

Thanks, I did not realize how the different parts work together. Actually, I still don't, but now I have some terms to google on.


> You could write a short script or alias to select
> lines that you want so that "aptitude search qt |
> grep ruby | scriptA 2 5" would pull out those two
> lines and put them in a hidden file that can be
> found by a second script. Then "scriptB sudo
> apt-get install" would run the install on every line
> of the file.

That might be a good exercise, I'll try that. Thanks.

---------- Post updated at 05:10 PM ---------- Previous update was at 05:03 PM ----------

I found screen this morning, which does most of what I am looking for:
Screen - Gentoo Linux Wiki
GNU Screen: an introduction and beginner's tutorial || kuro5hin.org
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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)