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error when call function in bash script

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Top Forums Shell Programming and Scripting error when call function in bash script
# 1  
Old 02-17-2010
error when call function in bash script
Dear all,

Could you please advice as I when call function i found the following error
" refills: command not found" note that refills is function name.

following also the function and how i call it
Code:
function refills 
{
    echo "formatting refills and telepin" >> $log
    awk -F, '{print $7","$1","$2","$3","$5","$6","$9","$10","$11","$12","$13","$14","$15","$16","$17","$18","$20","$21","$22","$23","$24","$25","$26","$27","$28","$29","$30","$31","$32","$33","$34","$35","$36","$37","$38","$39","$40","$41","$42","$43","$44","$45","$46","$47","$48","$49","$50","$51","$52","$53","$54","$55","$56","$57","$58","$59","$60","$61","$62}' $func_path/$func_tmp > $func_path/$func_out 2>> $log
}
.
.
.
.

#to call the function

refills;

Thanks in advance.
Last edited by zaxxon; 02-17-2010 at 07:21 AM.. Reason: use code tags please, ty
# 2  
Old 02-17-2010
try below :-

Code:
function refills {
    echo "formatting refills and telepin" >> $log
    awk -F, '{print $7","$1","$2","$3","$5","$6","$9","$10","$11","$12","$13","$14","$15","$16","$17","$18","$20","$21","$22","$23","$24","$25","$26","$27","$28","$29","$30","$31","$32","$33","$34","$35","$36","$37","$38","$39","$40","$41","$42","$43","$44","$45","$46","$47","$48","$49","$50","$51","$52","$53","$54","$55","$56","$57","$58","$59","$60","$61","$62}' $func_path/$func_tmp > $func_path/$func_out 2>> $log
}
.
.
.
.

#to call the function

refills;

# 3  
Old 02-17-2010
unfortunately the problem still exist
Dear ahmad,

Thank you very mauch for fast response but unfortunately the problem still exist.

Thanks,
Ahmed Gad
# 4  
Old 02-17-2010
Add a shebang in the head and try again:

Code:
#!/bin/bash
...
...

Or whatever is the path to your bash. Also you can leave out the ; behind calling the function.
# 5  
Old 02-17-2010
Gad there are no problem with the function I had tried it in my bash shell with successful o/p.

but try the other format of the functions and note the ";" & "\" below:-

Code:
refills () { \
    echo "formatting refills and telepin" >> $log ; \
awk -F, '{print $7","$1","$2","$3","$5","$6","$9","$10","$11","$12","$13","$14","$15","$16","$17","$18","$20","$21","$22","$23","$24","$25","$26","$27","$28","$29","$30","$31","$32","$33","$34","$35","$36","$37","$38","$39","$40","$41","$42","$43","$44","$45","$46","$47","$48","$49","$50","$51","$52","$53","$54","$55","$56","$57","$58","$59","$60","$61","$62}' $func_path/$func_tmp > $func_path/$func_out 2>> $log ; \

}

refills ;

# 6  
Old 02-17-2010
It is not working also
Dear zaxxon,

I already added the shebang in the script, also I tried to remove the simicolon, but unfortunately It is not working also,

- also i tried to put 2 () after the function
# 7  
Old 02-17-2010
Assuming that this is a modern bash/ksh/sh you were indeed mixing two alternative syntaxes for a function.

This should be correct. Note also that the semicolon at the end of each of your lines is not required or desirable. I can't think of any circumstance where a semicolon would be the last character on a line.

Code:
refills ()
{
echo "formatting refills and telepin" >> $log
awk -F, '{print $7","$1","$2","$3","$5","$6","$9","$10","$11","$12","$13","$14","$15","$16","$17","$18","$20","$21","$22","$23","$24","$25","$26","$27","$28","$29","$30","$31","$32","$33","$34","$35","$36","$37","$38","$39","$40","$41","$42","$43","$44","$45","$46","$47","$48","$49","$50","$51","$52","$53","$54","$55","$56","$57","$58","$59","$60","$61","$62}' $func_path/$func_tmp > $func_path/$func_out 2>> $log
}

refills
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