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How to use awk to classify file extension from input ls -l

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# 1  
Old 02-15-2010
How to use awk to classify file extension from input ls -l
i try to do this for a long time
input is command ls -l
and output is:

Code:
Number of files : xx 
Number of file type – awk : 5        total size: 2345 bytes  // file ex type .awk
Number of file type – dat : 10        total size:  233 bytes  // file ex type .dat
...
Number of unknown file type : 20    total size: 9879 bytes // no file type

i try to write awk script because this is my awk's practice
thank for any comment
ps. sorry for my poor english
Last edited by Scott; 02-23-2010 at 07:46 PM.. Reason: Code tags
# 2  
Old 02-15-2010
Hi. I think first you must get the extension and then increment a element in a dictionary. Finally you must print all the elements in dictionary
Code:
{
  #Get the extension and count
  if (match($9, /[^.]*$/)){
    count[substr($9,RSTART,RLENGTH)]++
  }else{
    count["Unknown"]++
  }
}
END{
  #Print all the counters
  for(x in count){
    print "x---"count[x]
  }
}

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