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awk code not working in some HP versions

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# 1  
Old 02-15-2010
awk code not working in some HP versions
Dear all,

Some one please help in solving this awk issue in HP.
The below code was working fine in HP version B.11.11 U 9000/800 but when the same was run B.11.31 U ia64 it failed. Smilie.
Code:
if awk 'BEGIN{if ('$var1' > 80); else exit 1}'
then
echo "Greater"
fi

# 2  
Old 02-15-2010
It just gives syntax errors on HPUX 11.11.
Have you copied the script correctly?
What is it designed to do?
# 3  
Old 02-15-2010
No change in the code..
But i think this server has some problem with the newline character ";". I tried putting "\" before ";", that too didnt work. Smilie
# 4  
Old 02-15-2010
Quote:
Originally Posted by engineer
No change in the code..
But i think this server has some problem with the newline character ";". I tried putting "\" before ";", that too didnt work. Smilie


---------- Post updated at 11:05 AM ---------- Previous update was at 11:05 AM ----------

Have you tried with

test $var1 -gt 80 && echo "greater"
# 5  
Old 02-15-2010
Try these examples
Code:
var1=81
awk -v var1=$var1 'BEGIN{ if (var1<81) { exit 1} else {exit} }' && echo "greater"
# or
[[ $var1 -gt 80 ]] && echo "greater"
var1=80
awk -v var1=$var1 'BEGIN{ if (var1<81) { exit 1} else {exit} }' && echo "greater"
[[ $var1 -gt 80 ]] && echo "greater"
echo "return status is $?, failure in this case"



You should have it as all shell - it is more effiicient than creating an awk child process for a simple compare. The shell approach also preserves the result of the compare in the $? variable so you can branch as needed. Just like the awk call.
# 6  
Old 02-16-2010
Thanks for all your help.

I knew the use of test and the script works but just wanted to know the reason for awk not working.
# 7  
Old 02-16-2010
The awk failed because it contained several syntax errors. When you study jim mcnamara's suggestions you will notice that space characters and the correct use of braces are paramount.
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