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Shell Programming and Scripting

Create helpmenu for shell script

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# 1  
Old 02-12-2010
Create helpmenu for shell script
Hello Community,

I wrote a shell script, which (with some help of a few members of this forumSmilie) is doing what it should do... Now I think, it would be nice to tell the user of my little program, how he/she can use it. For this point, I created a help option, that can be called with "-h" after the programname. But thats not exactly what I want to have. I would prefer, that there's a additional "help-menu", that opens if the user just type the program-name without any option or argument. I've got an examplte for this:

Code:
sebi@notebook:~$ sudo
usage: sudo [-n] -h | -K | -k | -L | -V | -v
usage: sudo -l[l] [-AnS] [-g groupname|#gid] [-U username] [-u username|#uid] [-g groupname|#gid] [command]
usage: sudo [-AbEHnPS] [-C fd] [-g groupname|#gid] [-p prompt] [-u username|#uid] [-g groupname|#gid] [VAR=value] [-i|-s] [<command>]
usage: sudo -e [-AnS] [-C fd] [-g groupname|#gid] [-p prompt] [-u username|#uid] file ...

Something like that. How can I create a help menu like that?

Regards
Sebi
# 2  
Old 02-12-2010
2 ways come to mind:
  1. If there are no arguments ($# is 0), or there's a single argument '-h', call a function "help" which displays the help & exits
  2. Same as above with some getopts sugar coating
# 3  
Old 02-16-2010
Code:
PRG=$0
usage()
{
    echo "usage:$PRG ...." >&2
    exit 1
}

[ "$#" -lt 1 ] && usage

# parse commandline
while [ $# -gt 0 ]
do
      arg="$1"
      case "$arg" in
         -d|--debug) echo "debug" ;;
         -h|--help) usage ;;
         --) shift; break;;  # no more options
         -*) usage ;; 
         *) break;; # not option, its some argument
       esac
       shift
done

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