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Shell Programming and Scripting

issue with for loop

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# 1  
Old 02-11-2010
issue with for loop
Hi All,

Please help me with for loop!!!!

I have to put the limit with for loop like
Code:
  For I in 1..30 
  Do 
  Echo $i
  Done

I want my output to be like 1
2
3
4
5
6
7
8
9 till 30


Thanks
Last edited by vbe; 02-11-2010 at 09:36 AM.. Reason: code tags please
# 2  
Old 02-11-2010
Code:
for i in {1..30}; do echo $i; done

# 3  
Old 02-11-2010
I did tried before the same and i am getting syntax error !!!! which shell you are using ..

i tried the same with bash, sh and ksh however no luck

Not sure if it make sense or not .. i am using SunOS
# 4  
Old 02-11-2010
Is there a reason to not use while loop (just asking...)?
In which case you can add a counter...
# 5  
Old 02-11-2010
Quote:
Originally Posted by anchal_khare
Code:
for i in {1..30}; do echo $i; done

this is valid for bash shell,

try:

Code:
for ((i=1;i<=30;i++)); do echo $d; done

which shell do you have ?
Last edited by clx; 02-11-2010 at 10:39 AM.. Reason: some edit
# 6  
Old 02-11-2010
Issue with bash

Quote:
bash-2.03$ bash testf
testf: line 1: syntax error near unexpected token `;'
testf: line 1: `for in {1..30}; do echo $i; done'
Code
Quote:
for ((i=1;i<=30;i++)); do echo $d; done
error
Quote:
testf1: syntax error at line 1: `(' unexpected
# 7  
Old 02-11-2010
If you have an old Bourne shell:

Code:
let i=1
while [ $i -le 30 ]
do
   echo $i
   let i=$i+1
done

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