Shell Programming and Scripting

for j in `find $i -name "abc*" -type d`; do
              unzip -qT $j/\* 2>>/dev/null;
             if [ $? -ne 0 ]; then
                for k in `find $j -type f`; do
                   unzip -qT $k 2>>/dev/null;
                done
             fi
done

((i++)); (($i%5000)) || echo "$i files processed"

for j in `find $i -name "abc*" -type d`; do 
// Here $i is directory.
((i++)); (($i%5000)) || echo "$i files processed"
// Here it will display the count of sub-directories. I need to display list of
files in sub-directories.

for FILE in $(ls abc*/*) # This should work
do
    ((n++)); (($n%5000)) || echo "$n files processed"
    unzip -qT $FILE 2>>/dev/null || echo "Error in file $FILE"
done

 for FILE in $(ls $j) # This should work
// $j - last level subdirectory which has list of zipfiles without .zip extension
do
   ((n++)); (($n%5000)) || echo "$n files processed" 
    
    unzip -qT $FILE 2>>/dev/null 
    if [ $? -ne 0 ]; then
           echo $FILE is BAD 
    fi
   
done

 for k in `find $j -type f`; do

(( n+=$(find $j -type f | wc -l) ))