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grep middle word between two patterns

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# 1  
Old 02-08-2010
grep middle word between two patterns
Hi,
I'm currently working on a shell script to automate a backup check on oracle database. My requirement is to grep the words between two delimiters and pass on to a variable..

for ex I have following values in my log file...
Code:
(DB_NAME), (163.24 25), (16/02/10 23:40), (COMPLETED),

I want to grep only the values between opening and closing paranthesis and pass that value to shell variables.
Code:
A='DB_NAME'
B='163.24 25'
C='16/02/10 23:40'
D='COMPLETED'

The values between the delimiters are bound to change based on my backup check, so the check has to be performed based on delimiters - ().

Can someone please help!!
Last edited by Scott; 02-09-2010 at 03:56 AM.. Reason: Please use code tags
# 2  
Old 02-08-2010
Do you want to grep particular line or do you want to process all lines?
# 3  
Old 02-08-2010
How about ...

Code:
[house@leonov] INPUT="(DB_NAME), (163.24 25), (16/02/10 23:40), (COMPLETED),"; \
[............] A=$( echo $INPUT | awk -F "[()]" '{print $2}' ); \
[............] B=$( echo $INPUT | awk -F "[()]" '{print $4}' ); \
[............] C=$( echo $INPUT | awk -F "[()]" '{print $6}' ); \
[............] D=$( echo $INPUT | awk -F "[()]" '{print $8}' ); \
[............] echo "A='$A', B='$B', C='$C', D='$D'"
A='DB_NAME', B='163.24 25', C='16/02/10 23:40', D='COMPLETED'

# 4  
Old 02-08-2010
Code:
#! /bin/ksh

INPUT="(DB_NAME), (163.24 25), (16/02/10 23:40), (COMPLETED), "

echo $INPUT | nawk -F",|, " ' {
        for( i = 65; i <= 68; i++ )
                printf("\"%c\"%s\n", i,"="$(i - 64))
        }' | tr "()" "'"

Output: -

Code:
"A"='DB_NAME'
"B"='163.24 25'
"C"='16/02/10 23:40'
"D"='COMPLETED'



---------- Post updated at 11:35 PM ---------- Previous update was at 08:37 PM ----------

Actually the delimiter is the , not ().

If you want to do the assignement to the variables form the script you could try this: -

Code:
#! /bin/ksh
 
INPUT="(DB_NAME), (163.24 25), (16/02/10 23:40), (COMPLETED), "
 
echo $INPUT | nawk -F",|, " ' {
        for( i = 65; i <= 68; i++ )
                printf("export %c%s\n", i,"="$(i - 64))
        }' | tr "()" "'" > tmp_file
 
. tmp_file 2>/dev/null || echo "Error in export file"
 
echo "A=$A"
echo "B=$B"
echo "C=$C"
echo "D=$D"
 
rm -f tmp_file

Output: -

Code:
A=DB_NAME
B=163.24 25
C=16/02/10 23:40
D=COMPLETED

# 5  
Old 02-09-2010
Computer
Hi All,
Thanks so much for all the replies. Both the suggestions worked for me,
Thats the output I was looking for ..

Thanks!
# 6  
Old 02-09-2010
Actually I have just realised the test of the tmp_file for errors does not work, it needs to be executed in a subshell like: -

Code:
if ! tmp_file >/dev/null 2>&1

Then take any remedial action within the if block.
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