Am doing continuous backup of mailboxes using rsync.
So whenever a new mail arrives it is automatically copied on backup server.
When a new mail arrives it is named as xyz:2, when it is read by the email client an S is appended xyz:2,S
Eventually , 2 copies of the same file exist on the backup server with different names while on the Mailserver only xyz:2,S exists.
e.g
on mail server: xyz:2,RS
on backup server: xyz:2, xyz:2,S xyz:2,RS
So in 1 directory i can have 3 copies of file xyz & 2 copies of file abc.
Can anyone help how i can remove the oldest files(xyz:2,) and keep only the most recent one on the backup server ?
If a mail file is deleted from the mail server , using --delete will delete on backup server as well.
Am running rsync regularly & files on backup server are deleted by a script only if they have a certain age e.g 10days
---------- Post updated at 06:39 PM ---------- Previous update was at 05:58 PM ----------
Quote:
Originally Posted by Anu_1
I am very new in unix but will it help if you use..
ls -rt| tail -1 ==> this will get you the most current file
coolatt, if I'm reading this right, you want to delete from the backup server, for each xyz,2* group, all but the most recent file pertaining to each group.
I recreated your directory with the following files. Please note the order in which they were created (ls -rt):
I'm beginning to get a bit confused about what you want... Do you want to have the same files on the mail server and the backup server (as in, get a list of all the files currently on the mail server and delete from the backup server anything that's not in that list)?
So, I have text files,
one "fail.txt"
And one
"color.txt"
I now want to use a command line (DOS) to remove ANY line that is PRESENT IN BOTH from each text file.
Afterwards there shall be no duplicate lines. (1 Reply)
Hi,
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12347___PP___0902___AA. txt
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This is too hard for me maybe someone could help.
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