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Shell Programming and Scripting

Display string at line number

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# 1  
Old 02-01-2010
Display string at line number
I have a code here , which should display lines 6,10,14,18,35 of a text file

Code:
 
#!/bin/ksh
line[1]=6
line[2]=10
line[3]=14
line[4]=18
line[5]=35
for i in 1 2 3 4 5
do
val=`echo ${line[$i]}`
act=`awk 'NR~/^($val)$/' db_CHECKOUT.txt`
done;

This code is not working. The purpose of the line below is to grep for line 6 from the file db_CHECKOUT.txt. It works fine when it has a number bt when i replace a variable "%val" in the above code its doesnt give any result


Code:
 
awk 'NR~/^(6)$/' db_CHECKOUT.txt

# 2  
Old 02-01-2010
Code:
act=`awk 'NR~/^("'"$val"'")$/' db_CHECKOUT.txt`

or
Code:
act=`awk 'NR~/^(v)$/' v=$val db_CHECKOUT.txt`

# 3  
Old 02-01-2010
Thanks for the reply..I replaced the code with the line that you posted ..Its displaying 5 blank lines...although my text file has data on each line
# 4  
Old 02-01-2010
Perhaps this might work for you (as a replacement for you script)?
Code:
sed -n '6p;10p;14p;18p;35p' infile

or
Code:
sed -ne6p -e10p -e14p -e18p -e35p infile

Last edited by Scrutinizer; 02-01-2010 at 05:36 PM..
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