Shell Programming and Scripting

Hi Guys,

I have a file as follows:

Code:

 
wwe
khfgv
jfo
wwe
jhgfd
wwe
wwe
hoaha
hao
lkahe
wwe

I want to count the lines between the consecutive wwe's and store the count in variables. So for example the first variable value will be 2, (as there are two lines between the wwe's) second variable will be 1. The third variable value should be 0 and the fourth will be 3. I would prefer the awk solution and I guess using arrays will be better.

I started out with a simple statement:

Code:

awk '!/wwe/' file

but this does not give me missing lines (where there is no entry between the two consecutive wwe's.

Thanks in advance for your help.

Code:

awk ' /wwe/ { if ( f!="") {print f-1}; f=0;f1=1 } f1 { f++ } ' file

Thanks, that worked.

Code:

awk '/wwe/{if(p)print NR-p-1;p=NR}' infile

Code:

2
1
0
3

Code:

my $flag =0 ;
my $cnt = 0;
while(<DATA>){
	if(/wwe/){
		if($flag eq 0){
			$flag=1;
			next;
		}
		print $cnt,"\n" if $flag eq 1;
		$cnt=0;
	}
	else{
		$cnt++;
	}
}
__DATA__
wwe
khfgv
jfo
wwe
jhgfd
wwe
wwe
hoaha
hao
lkahe
wwe

Thanks,summer_cherry.

Now I want to print the lines between only the first two consecutive "wwe" lines. So my file output should be:

Code:

khfgv
jfo

How can I do this?

I tried using:

Code:

awk '! /wwe/,/wwe/' file

but that gives me

Code:

khfgv
jfo
wwe
jhgfd
wwe
hoaha
hao
lkahe
wwe

Code:

awk '/wwe/ && ++c <= 2 {getline; print}' file