Shell Programming and Scripting

That is giving me this output:

Code:

khfgv
jhgfd

I want:

Code:

khfgv
jfo

Sorry, I misread the question. It should be:

Code:

awk '/wwe/{getline; print; getline; print; exit}' file

Code:

awk '/wwe/{p++;next}p<2' infile

Sorry I was not clear on the question. I may have multiple lines between the two patterns for example:

Code:

wwe
khfgv
jfo
mmm
nnn
wwe
jhgfd
wwe
wwe
hoaha
hao
lkahe
wwe

I was looking for a more general solution. Your script will print only the two lines, but if I want to print all the lines ONLY between the first two consecutive wwe's. In this case I should get:

Code:

khfgv
jfo
mmm
nnn

Are the two print statements for the two lines?How can I modify the script to print all lines between the two wwe's?

Thanks for your patience on this.

To handle a variable number of records:

Code:

awk '/wwe/&&_++{exit}!/wwe/' infile

Thanks, radulov. It worked.

One last question: how can you modify the script if wwe is not the first word on the line; in other words, if my file was like this:

Code:

sss wwe
kkk khfgv
aaa jfo
qqq mmm
kjgfd nnn
rrr wwe
ttt jhgfd
uuu wwe
ooo wwe
ppp hoaha
ddd hao
fff lkahe
hhh wwe

and I want:

Code:

kkk khfgv
aaa jfo
qqq mmm
kjgfd nnn

Should I use $2 = in your awk script? Thanks again for your help.

Edit: I tried it and it worked. Sorry for the confusion.

No modification should be needed ...