Shell Programming and Scripting

Hi,
when I run ls -l I get the following command (I already know ls) :

Code:

rwxrwxrwx 2 andrew andrew 4096 2010-01-25 22:00 test.txt
rwxrwxrwx 2 andrew andrew 4096 2010-01-25 21:01 test1.txt
rwxrwxrwx 3 andrew andrew 4096 2010-01-25 20:45 test2.txt
rwxrwxrwx 1 andrew andrew 4096 2010-01-25 01:12 test3.txt

I want to write a bash program that uses : cut, grep, sed and pipes
and makes the output asfollow (I know ls give me the name only,but i have to use ls -l):

Code:

-test.txt
-test1.txt
-test2.txt
-test3.txt

(there has to be a dash)


what should I use(I just know I should use the pipe):
ls -l |

am not sure, Is this what are you looking for ?

Code:

ls -l|awk '{ print "-"$8 }'

Hello,
Searching forum database you could find this solution very easily:

Code:

ls -l | awk '/^-/ {print "-"$9}'

Hmmm, sounds like home work to me.

Code:

ls -l | awk '/^-/ {print "-"$NF}'

Code:

ls -l | sed -n 's/^-.* /-/p'

Look like a homework to me (see Forum Rules) if not:

Code:

for i in *.txt;do echo -${i};done

You don't need cut, grep, sed and pipes.

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