Shell Programming and Scripting

I have a file name version.properties with the following data:

major.version=14
minor.version=234

I'm trying to write a grep expression to only put "14" to stdout. The following is not working.

grep "major.version=([0-9]+)" version.properties

What am I doing wrong?

Try egrep.

That's progress, but egrep returns "major.version=14" ... I only want the 14.

Try:

Code:

sed 's/major\.version=\([0-9]\+\)/\1/'

-or-

Code:

sed 's/major\.version=\([0-9]\{1,\}\)/\1/'

-or-

Code:

sed -r 's/major\.version=([0-9]+)/\1/'

-or-

Code:

awk -F= '$1=="major.version"{print $2}'

I tried all four of those. I'm using cygwin's sed and awk. The first three returned everything after the first equal sign. The awk statement returned nothing at all.

D:\>sed 's/major\.version=\([0-9]\+\)/\1/' version.properties
14
minor.version=234

D:\>sed 's/major\.version=\([0-9]\{1,\}\)/\1/' version.properties
14
minor.version=234

D:\>sed -r 's/major\.version=([0-9]+)/\1/' version.properties
14
minor.version=234

D:\>awk -F= '$1=="major.version"{print $2}' version.properties

---------- Post updated at 02:22 PM ---------- Previous update was at 02:15 PM ----------

gawk works beautifully. Thank you.

---------- Post updated at 02:30 PM ---------- Previous update was at 02:22 PM ----------

Is there any way to get the awk command to print "14.234"?

Oops, that should be:

Code:

sed -n 's/major\.version=\([0-9]\+\)/\1/p'

-or-

Code:

sed -n 's/major\.version=\([0-9]\{1,\}\)/\1/p'

-or-

Code:

sed -nr 's/major\.version=([0-9]+)/\1/p'

---------- Post updated at 20:44 ---------- Previous update was at 20:33 ----------

Code:

awk -F= '$1=="major.version"{a=$2}$1=="minor.version"{b=$2}END{print a"."b}'

That's awesome. Thank you!