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Replacing Port number Using Sed

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# 1  
Old 01-22-2010
Bug Replacing Port number Using Sed
Hi
Im trying to replace http port value.However for some reason its not working.Can you guys take a look and hit me with suggestions please.Your help is much appreciated.

Code:
echo "Enter Value"
read ans
sed -i "s/http-port = 80 /http-port = $ans/g" demo

Note:demo is the filename


Thanks guys
CK
Last edited by Scott; 01-22-2010 at 05:53 PM.. Reason: Please use code tags
# 2  
Old 01-22-2010
you getting any error??
# 3  
Old 01-22-2010
Im not getting errors however its not working meaning its taking the value however it is not changing the value..
# 4  
Old 01-22-2010
can you post the input data line from file demo..
# 5  
Old 01-22-2010
Here is what im getting
Code:
host$ cat demo
http-port = 80

host$ ./test2
enter value
81

host$ cat demo
http-port = 80

Filename:test2 has the code I posted earlier and it should change the http-port value in Filename:demo.


The value in the file:demo should be 81 after executing test2, which is not happening..

Thanks
CK
Last edited by Scott; 01-22-2010 at 05:53 PM.. Reason: Please use code tags
# 6  
Old 01-22-2010
Hi.

Based on your original sed:

Code:
sed "s/http-port = 80 /http-port = $ans/g" demo

all I can see that is wrong is a space before the / in the substitution part of your sed expression:

i.e. should be
Code:
sed "s/http-port = 80/http-port = $ans/g" demo

Code:
$ cat Test
ans=81
sed "s/http-port = 80 /http-port = $ans/g" demo
$ ./Test
http-port = 80

$ cat Test
ans=81
sed "s/http-port = 80/http-port = $ans/g" demo
$ ./Test
http-port = 81

# 7  
Old 01-22-2010
Yep, you are right.thank you sir, its working now.
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