Hello,
I know little about shell scripting and creating a script, and worked fine in the command line. But not work in the cron. Below you could see the script
So far I found when I use corn following part not working, nothing goes to the processedfiles file.
This work perfect in command line. Corn job and command line use by the same user.
Hope some one could direct me to correct path.
thank you,
Last edited by pludi; 01-21-2010 at 03:47 AM..
Reason: code tags, please...
This is a topic which very often comes up. Starting something on the command line is not the same environment like when started via cron. Environment variables will not be set like PATH and so on.
You can either use the search function of the forum and/or read this: https://www.unix.com/answers-frequent...n-crontab.html
Please post the exact cron line and state when you expect the cron to run.
Please state which Operating System you have.
Remember that the script will need to be invoked with the full path name of the script (not as ./scriptname).
If the cron is failing for some reason the error messages will be in mail for the cron user (e.g. root). Also check that the cron runs at all by looking at the logfile for your cron (see "man cron" to find the name of the logfile). How did you add the job to the crontab?
I'm using Ubuntu 9.10 server 64 bit.
I changed the location of the script to simplify the test
so far I try following cron lines and syslog show script executed but nothing goes to the processedfiles
49 08 * * * /home/malik/test/Tmoustart
02 09 * * * sh /home/malik/test/Tmoustar
This is my modified script.
Still I can see when I run on the terminal worked fine. But in the cron following part with ls not working.
I add . $HOME/.profile to pick-up the environment variables. Hope that's the correct way.
---------- Post updated at 11:18 AM ---------- Previous update was at 09:05 AM ----------
Now I narrow it down to grep command
I use following simple script
Output from command line
Output from cron
For some reason grep not working. I tested in three computers with Ubuntu 64 bit and 32 bit.
Any body know any other way I could do this?
Thank you,
---------- Post updated at 02:31 PM ---------- Previous update was at 11:18 AM ----------
Hello all I mange to fix the problem using find command. But still I do not know why grep failed. I found grep failed with any number. if I use characters work fine.
Basically I used the script to find last 3 days files in a folder and copy to another location.
using find command as below I mange to do the same and also that make my script smaller too
find /var/lct/mou2/processed/ -mtime -2 > /home/trans/mou/processedfiles
Now all worked fine with cron and command line. using the content of the processedfiles I can copy the files.
Thank you for helping me
Last edited by pludi; 01-22-2010 at 02:29 AM..
Reason: code tags, please...
The problem I see is that the date format in $TODAY and $YESTERDAY does not match the date format in your "ls" from cron. Maybe you have an alias for "ls" in the user acount which produces the non-standard date format?
In general the match string for grep should be in double quotes.
As you have deduced it is better to use "find" in this circumstance anyway.
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