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While read line loop

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# 8  
Old 01-19-2010
further to anchal_khare . Protecting any space characters in $line and avoiding syntax issues in the "if" statement when $found is null. Not clear (to me) where the value of $USER comes from.

Code:
#!/bin/bash

yy="${1}"

count=1

while read line
do

        found=$(echo "${line}"|grep "${USER}")
        if [ ! "${found}""X" = "X" ]
        then
              echo "${count}) ${line}" >> filesave
        fi
        count=$((count+1))


done < $yy

# 9  
Old 01-19-2010
@Anchal - Many thanks I got it working using the found variable but I have been told there is a way using just the while loop.....


@Franklin - input file is "env" command's output. Am unable to post as it contains sensitive information.


I appended the contents on env to the yy file first using the following format:
env >> yy
env >> yy
env >> yy


Here is what I have done now and I get an output but it isn't the right one.......

Code:
#!/bin/bash

yy=$1
count=1
lineinput=$(echo $line | grep $USER)
while read line
do

        echo $count")" $line >> filesave
        count=$((count+1))
 
done < yy

# 10  
Old 01-19-2010
Quote:
Originally Posted by BundBash
@Franklin - input file is "env" command's output. Am unable to post as it contains sensitive information.
Something like this?

Code:
env | awk -v var="$USER" '$0 ~ var{print NR ") " $0}'

# 11  
Old 01-19-2010
yes franklin but I need to carry it out using only a while loop and no use of the sed or awk commands.....
# 12  
Old 01-19-2010
Quote:
Originally Posted by BundBash
yes franklin but I need to carry it out using only a while loop and no use of the sed or awk commands.....
Is this a homework question?
# 13  
Old 01-19-2010
no am learning bash scripting for a new job.....it's not homework
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