Shell Programming and Scripting

Hi ,

I have incremental file FILE1 which locate in directory /asd/ This directory contains log files whose name entries goes in FILE1

how to make shell scripts for following condition

shell script executes on

day1
FILE1 entry ---->
1.log
2.log
3.log
4.log

script read 4.log Checks if exist in /xyz/
If "Yes" then exit
If "No" the cp -r /asd/4.log /xyz/

day2
FILE1 entry -------->
1.log
2.log
3.log
4.log
5.log

script read 5.log Checks if exist in /xyz/
If "Yes" then exit
If "No" then cp -r /asd/5.log /xyz/

script read 4. log Checks if exist in /xyz/
If "Yes" then exit
If "No" then cp -r /asd/4.log /xyz/

Thanks

try this one

Code:

 
for i in `cat FILE1 ` ; do if [ ! -f /xyz/$i ]; then cp $i /xyz/$i ; fi  ; done

Code:

 
for i in `cat FILE1 ` ; do if [ ! -f /xyz/$i ]; then cp /asd/$i /xyz/$i ; fi  ; done

I made following scripts but when second time execute this query it copying the new file and in last shows such error "7.log.gz already exists; do you wish to overwrite (y or n)? n" what changes to be done in script that it copies only new file after it exits from loop

Code:

#!/bin/bash

awk '{ a[NR]=$0 } END { for(i=NR; i; --i) print a[i] } ' /home/bin/FILE1 > /home/bin/FILE2 // this command will reverse the order latest first
sleep 1
echo "Today is $(date)"
echo "--------------------"

for i in `cat /home/bin/FILE2`;
do
  if [ ! -f /home/xyz/$i ];
  then cp -r  /home/bin/$i /home/xyz/$i ;
    gzip -9  /home/xyz/$i
    echo "Copying binlogs : $i"
  else
    exit 0
  fi  ;
done
exit 0

Hi.

By "copies only new files", do you mean only if the file does not already exist?

You could change your cp command to something like:

Code:

false | cp -ifr  /home/bin/$i /home/xyz/$i 2> /dev/null

That's the same as if your cp has the -n option, then:

Code:

cp -nr  /home/bin/$i /home/xyz/$i

If you meant "update files" without being asked, change it to:

Code:

cp -fr  /home/bin/$i /home/xyz/$i

Not sure what you mean by "after it exits from loop"?