Print from second column onwards if $1<=40 using awk


 
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# 8  
Old 01-12-2010
Quote:
Originally Posted by jim mcnamara
Code:
awk '$1<=40 { $0=substr($0, index($0,$2)); print $0 } 
       $1>40 {print $0 } ' infile > outfile

If $1 and $2 is same number then code does not give intended output.
Quote:
$ awk '$1<=40 { $0=substr($0, index($0,$2)); print $0 }
> $1>40 {print $0 } ' file
10 10 21 32 43 54
10 25 36 47 58
19 20 31 42 53
10 24 35 46 57
50 10 28 39 40 51
# 9  
Old 01-12-2010
Many thanks for the replies. Smilie
# 10  
Old 01-12-2010
Code:
while read first rest; do [ $first -le 40 ] && echo "$rest"; done < data

# 11  
Old 01-12-2010
Quote:
Originally Posted by kristinu
I need to check if $1 <= 40, then print from $2 onwards.
If $1 > 40, the line is not printed.
Code:
awk '$1>40{next}{sub($1FS,X)}1' infile

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