Shell Programming and Scripting

Hi!

I have a parameter in an existing script, let's call the parameter param1 and the script - script1.

I have another script - script2, which receives param1 and returns a certain value.

I would like this value to be returned inside param1.

There is no problem with script2, it runs perfectly.

I tried many things like

@ param1 = `script2 $param1`
this one returns an error: "script2: command not found."

or
@ param1 = `echo script2 $param1`
this one returns an error: "@: expression syntax."

or
@ param1 = `script2 param1`
this one returns: "script2: no match."

or
@ param1 = `echo script2 param1`
this one returns: "echo: no match."

If you have any idea on how to solve this, please reply to this thread.

Thank you and have a nice weekend,
Shira.

Replace

Code:

@ param1 = `script2 $param1`

with

Code:

@ param1 = `perl script2  $param1`

Also if script1 and script2 are not in the same dir from which you are executing the script then use the full path of the script.

Note : i assume script2 is a perl script , hence used perl. If its in some other language define the appropriate usage

HTH,
PL

Hi!

Thanks for the reply!
Actually I'm not using perl but csh.

The files are in the same path.

I actually did this kind of thing once, but I forgot how to do it.
But I'm sure that it wasn't that way.

I thought about doing some pipelining but it didn't succeed as well...

Thanks,
Shira.

Hi shira ,

Code:

@ param1 = `script2 $param1`
this one returns an error: "script2: command not found."

This means that shell is not able to execute the script.

Normally when you run the script from the command line you use

Eg:- sh test_script.sh or
./test_script.sh


similarly when using the backtick operator use the appropriate usage

HTH,
PL

Hi,

I just found out what was my problem:
I needed to add "./".

So the correct answer is:

@ param1 = `./script2 $param1`

Thanks for the patience and the help,
Shira.

You can also do

Code:

source scriptname