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Shell Programming and Scripting

Sum of three columns - in 4N columns file

 
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Old 01-06-2010
Sum of three columns - in 4N columns file
Hi All,
happy new year.

I have a file with 4xN columns like

Code:
0.0000e+00	0.0000e+00	7.199E+07	7.123E+07	6.976E+07	6.482E+07	5.256E+07	2.523E+07
0.0000e+00	0.0000e+00	8.641E+07	8.550E+07	8.373E+07	7.780E+07	6.309E+07	3.028E+07
0.0000e+00	0.0000e+00	1.017E+08	1.007E+08	9.857E+07	9.159E+07	7.427E+07	3.565E+07
0.0000e+00	0.0000e+00	1.178E+08	1.166E+08	1.142E+08	1.061E+08	8.603E+07	4.130E+07
0.0000e+00	0.0000e+00	1.347E+08	1.333E+08	1.305E+08	1.213E+08	9.832E+07	4.719E+07
0.0000e+00	0.0000e+00	1.521E+08	1.505E+08	1.474E+08	1.370E+08	1.111E+08	5.331E+07

In this case N=2, but it can be what ever number.
I would like to replace
the 0's in column 1 with the sum of the column N+1,2N+1,3N+1
the 0's in column 2 with the sum of the column N+2,2N+2,3N+2
...
the 0's in column N with the sum of the column N+N,2N+N,3N+N

At the moment I'm using the following script which works fine if N=1

Code:
awk -F'\t' '
  (/^[0-9]/ && $1 == 0 && $1 = sprintf("%.4E",$2 + $3 + $4)) || -3
  ' OFS='\t' filename

Any idea how to genaralize the code?
Thank you,
Sarah
Last edited by f_o_555; 01-06-2010 at 11:58 AM..
 
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