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KSH variable containing piped commands

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# 1  
Old 01-02-2010
KSH variable containing piped commands
Hi,
I am trying to execute a bunch of piped command which are stored in a variable, but only one command executed at a time, and rest of the pipes, commands and their arguments are considered as argument to the very first command.
Can you please help me in this?

Code:
bash-2.05$ cat test.sh
#!/usr/bin/ksh
xyz="ls -lrt | wc -l"
echo $($xyz)
bash-2.05$ ./test.sh
|: No such file or directory
wc: No such file or directory
-l: No such file or directory

bash-2.05$


-- Prashant.
# 2  
Old 01-02-2010
Quote:
Originally Posted by prashant.ladha
Code:
#!/usr/bin/ksh
xyz="ls -lrt | wc -l"
echo $($xyz)

Code:
xyz=$(ls -lrt | wc -l) # Use on of both statements 
xyz=`ls -lrt | wc -l` # with $() or `` (backticks)
echo $xyz

If you really want to use a string
Code:
xyz="ls -lrt | wc -l"
eval "$xyz"

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