This should get rid of spaces around the backslash:
It creates a label a ( a: )
It then joins two lines ( N )
After that leadings space before and after a \ followed by a linefeed (\n) get replaced by a single space
Then it branches (b) to label a.
This should get rid of spaces around the backslash:
It creates a label a ( a: )
It then joins two lines ( N )
After that leadings space before and after a \ followed by a linefeed (\n) get replaced by a single space
Then it branches (b) to label a.
This works great. Thanks :-)
OK, you've given me pretty much exactly what I asked for but this has only highlighted the fact that I mis-stated exactly what I wanted. Ultimately, I'm trying to generate a list of hosts that are represented in the sudoers file. This sed statement (which actually only works if I use gsed on my Solaris 10 host) now leaves me with something like this:
OK, I can removed blank lines with grep or awk and I can chop off everything up to the = character with another sed statement and I might use tr, for example, to replace all the , characters with a newline character and I'm sure this would all get me what I want.
But ... could it ALL be done in a single command? List every host that's represented in the sudoers file?
- CDM
---------- Post updated at 11:22 AM ---------- Previous update was at 11:11 AM ----------
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