it never enter's the if even when the name is right
Code:
echo "Name:"
read Name
prev=`cut -d ";" -f1-3 funcionarios.cvs`
for linha in "$prev"
do
fun=`echo "$linha" | cut -d ";" -f2`
if [ "$Nome" = "fun" ]; then
echo "It's the same"
fi
done
What is Nome in your if-statement?
If that should be Name, you should perhaps proof-read your code before asking.
But the rest of the code does not do what you expect it to do. You can see what happens by using echo statements with the variable names.
The preferred method for this type of operation is something like this:
Code:
echo "Name:"
read $input_name
while IFS=";" read code name location
do
if [ "$input_name" = "$name" ]
then
echo $code
fi
done < funcionarios.csv
Last edited by Scrutinizer; 12-24-2009 at 05:26 PM..
I am using : << cut / cut to comment out block of code.
Works fine on few lines of script, then it gives me this cryptic error when I try to comment out about 80 lines.
The "warning " is at last line of script.
done < results
169 echo "END read all positioning parameters"
170... (8 Replies)
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g h i
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Hi
Can anyone what I am doing wrong while using cut command.
for f in *.log
do
logfilename=$f
Log "Log file Name: $logfilename"
logfile1=`basename $logfilename .log`
flength=${#logfile1}
Log "file length $flength"
from_length=$(($flength - 15))
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I have some weird problem that kinda baffles me. Say I have the following test file:
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This is a test line
This is the second test line
And yeah, this is the third test line
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