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1. UNIX for Beginners Questions & Answers
hello !
I have to remove string between a number and set of characters. For example,
35818 -stress - - -stress - - - - - - DB-3754
44412 caul kid notify DB-3747
54432 roberto -, notify DB-3725
55522 aws _ _int _ _classified 2_a _a 2_m _m 2_classified 2_search... (7 Replies)
Discussion started by: ManoharMa
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2. Shell Programming and Scripting
I was curious to know how to write into my shell script to remove a character. The character I want to remove is  within a .html file. (18 Replies)
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3. Shell Programming and Scripting
I am outputting a line like this
print $2 "/" $4The last character though is a ":" and I want to remove it. Is there any neat way to remove it? Or am I forced to do something like this:
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In bash, how can one remove the last character of a string? In perl, the chop function would remove the last character. However, I do not know how to do the same job in bash.
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5. Shell Programming and Scripting
How can i remove the first and last character of strings like below:
"^^^613*"
"admt130"
"^^^613*"
"123456"
"adg8484"
"DQitYV09dh1C"
Means i wanna remove the quotes("").
Please help (17 Replies)
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6. Shell Programming and Scripting
Hi there,
i need some help to remove all occurrences of a certain character at the beginning of a string.
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7. Shell Programming and Scripting
Hello!
Please bare with me, I'm a total newbie to scripting. Here's the sudo code of what I'm trying to do:
Get file name
Does file exist?
If true
get length of file name
get network id (this will be the last 3 numbers of the file name)
loop x 2
If... (1 Reply)
Discussion started by: KatieV
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8. Shell Programming and Scripting
Hello,
The last character is a comma ,
I have tried the following:
sed -e 's/\,$//' filename-to-read
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9. Shell Programming and Scripting
Hi all,
Does anyone know how to code in ksh that will remove the first character in a string variable and replace that variable without the first character?
Example:
var1=ktest1 will become var1=test1
var2=rtest2 will become var2=test2
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10. UNIX for Dummies Questions & Answers
I have a string "\/scratch\/databases\". I want
to have a new string "\/scratch\/databases" by cutting last '\' character using shell script. I can't do this
Please help me.
Thanks in advance
ThuongTranVN (4 Replies)
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uudemon(4) Kernel Interfaces Manual uudemon(4)
NAME
uudemon.admin, uudemon.cleanu, uudemon.hour, uudemon.poll - Administrative shell scripts for polling remote systems, cleaning up spool
directories, reporting status to the system administrator, and routine invocations of the uuxqt and uusched daemons
SYNOPSIS
These shell scripts reside in the following directory:
/usr/lib/uucp
DESCRIPTION
All the scripts can be run from the command line or can be run automatically by the cron daemon. To automatically run the scripts, remove
the comment character (#) from the beginning of the relevant line in the /var/spool/cron/crontabs/uucp file.
This script reports status to the system administrator. It issues the uustat command to find out the status of uucp jobs. It mails the
results to the uucp login ID. The script may be modified to send mail to any login ID such as the uucp administrative login ID (uucpa) or
root. This script cleans up the /var/spool/uucp and /var/spool/uucppublic directories by running the uucleanup command. The uucleanup com-
mand is run with the following parameters: -C7, -D7, X2, -o2, -W1. This script runs the uusched and uuxqt daemons in the background. This
script polls the systems listed in the /usr/lib/uucp/Poll file. The uudemon.poll script should be scheduled before the uudemon.hour
script. This allows uudemon.poll to create any command files before cron runs the uudemon.hour script.
FILES
Contains the uudemon.admin, uudemon.cleanu, uudemon.hour and uudemon.poll files. Contains the uucp file.
RELATED INFORMATION
Commands: cron(8), uucleanup(8), uusched(8), uuxqt(1)
Files: /usr/lib/uucp delim off
uudemon(4)