Shell Programming and Scripting

Hi guys!

I'll make this short... Is there any good way to get the day number that first matches the Monday column from the cal command output with awk (or any other text manipulator commands) ?

I'm sorry if my question wasn't clear at all.

For example...

One cal output would be

Code:

$ cal
       December 2009      
Sun Mon Tue Wed Thu Fri Sat  
         1   2   3   4   5
 6   7   8   9  10  11  12
13  14  15  16  17  18  19
20  21  22  23  24  25  26
27  28  29  30  31

Now, what I really need to get is the number of the first Monday in the month (I might also need, for example, the 3rd number of the Friday column, or any other number related to day that I need from that output).... In this case that would be the 7. I cannot think of anything since I have to consider that Monday might also be 1 or 2 in the 3rd line.....

Any idea?? I need this in order to setup a backup script for crontab, since as you know crontab is a little bit dumb.... but that doesn't matter.


Any help will be appreciated, thank you all in advance


P.S.: Sorry for my bad English...

This seems to do the trick:

Code:

cal -m 12 | awk '{ if (substr($0, 4, 2)*1) { print $2; exit } }'

7

Edit: Um. I should finish reading the question!

Try this -
https://www.unix.com/unix-advanced-ex...n-cron-do.html

Hi !

At first sight that gave a good output. I'll try applying it to what I need it for.

Perhaps I should think of another way of doing what I need, 'cause yeah as you say it's a bit messy...

Thank you alot scottn!!!


EDIT: Just saw your post Jim! I'm checking it right now.

If you have Perl and the Date::Manip module installed you can try this:

Code:

$ perl -le 'use Date::Manip;print UnixDate(ParseDate("1st Monday in December 2009"), "%d");'
07

$ perl -le 'use Date::Manip;print UnixDate(ParseDate("3rd Friday in December 2009"), "%d");'
18

The "bit messy" bit I already removed because as you said "at first sight...". Sorry about that

Sorry scottn, I don't get your post and don't understand why you deleted it.. (maybe language misunderstood)

Jim, yep that's why I was I asking this, my problem is something similar to that thread, I'll be reviewing that command. I've seen alot of answers regarding this issue, but I couldn't make work any of them. However, I came across with a post in a another forum where someone posted something that Perderabo came up with, that is

Code:

--------------------------------------------------------------------------------
#! /usr/bin/ksh
day=$(date +%d)
if ((day between 1 and 7, 8 and 14, etc....)) ; then
exec the mksysb command
fi
exit 1
--------------------------------------------------------------------------------

Maybe putting that script in the crontab telling it ro be ran on every monday (for example) will work..

SFNYC, unfortunately I don't have (and cannot install since it's a client LPAR) Date::Manip module.


Thank you all for your fast answers, this is very helpful.

Best regards