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Removing sections and leaving separators intact

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# 1  
Old 12-15-2009
Removing sections and leaving separators intact
I have an awk script like below

Code:
function abs(val) {
   return val > 0 ? val : -val
}

# 1. Main input loop, executed for each line of input
BEGIN { RS = ORS = ">" }

{ if ( NF > 2 )
    {
        if ( abs( $1 - $(NF-2) ) < 40 ) { print }
    }
}

The input file is something like this

Code:
>
10 0 0
10 0 0
>
13.0507 0 6.38077
12.9668 0.059253 6.16695
12.6077 0.244366 5.3721
12.2461 0.372226 4.64772
11.8815 0.447634 3.95789
11.5135 0.471699 3.2737
11.1415 0.442141 2.5654
10.7656 0.352356 1.79298
10.3858 0.188169 0.921258
10 0 0
>
13.507 0 6.38077
130.507 0 0
>

The code will sometimes remove some section enclosed within ">", otherwise leaving everything intact.

However when I run the script I am missing the first ">" sign.

Output is as

Code:
10 0 0
10 0 0
>
13.0507 0 6.38077
12.9668 0.059253 6.16695
12.6077 0.244366 5.3721
12.2461 0.372226 4.64772
11.8815 0.447634 3.95789
11.5135 0.471699 3.2737
11.1415 0.442141 2.5654
10.7656 0.352356 1.79298
10.3858 0.188169 0.921258
10 0 0
>


rather than

Code:
>
10 0 0
 10 0 0
 >
 13.0507 0 6.38077
 12.9668 0.059253 6.16695
 12.6077 0.244366 5.3721
 12.2461 0.372226 4.64772
 11.8815 0.447634 3.95789
 11.5135 0.471699 3.2737
 11.1415 0.442141 2.5654
 10.7656 0.352356 1.79298
 10.3858 0.188169 0.921258
 10 0 0
 >

# 2  
Old 12-15-2009
just put:

Code:
BEGIN{ print ">"; RS = ORS = ">" ; }

It won't print because it hasn't counted more than 2 fields yet.
You have your RECORD SEPARATOR set to >, this means that first one
has found no fields ( NF ) yet.
# 3  
Old 12-15-2009
Will try it

Can do

Code:
{ if ( NR == 1 ) print }

or

Code:
NR == 1 { print }



---------- Post updated at 02:48 PM ---------- Previous update was at 02:39 PM ----------

Works that way too. Thanks.
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