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Combining two variables in ksh

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# 1  
Old 12-10-2009
Combining two variables in ksh
I can't believe I can't figure this out... given this code:

Code:
CARS_DATA_LIST=`cat /tmp/file1 | awk '{print $1}' `
FMSA_DATA_LIST=`cat /tmp/file2 | awk '{print $1}' `

The value of each of the above variables is:

CARS = a b c d e f g
FMSA = a b c q r s

I want to declare a third variable that contains the unique elements of the other two variables. I tried:

Code:
NEW_VAR=`echo $CARS_DATA_LIST $FMSA_DATA_LIST | sort | uniq `
 
echo $NEW_VAR
a b c d e f g a b c q r s

Does not work... also added a -u flag to uniq with no luck... on a Solaris 10 box btw. Any help is appreciated.
# 2  
Old 12-10-2009
Code:
$ NEWVAR=`echo $(for i in $CARS $FMSA; do echo $i; done |sort |uniq)`

$ echo $NEWVAR
a b c d e f g q r s

There are probably easier ways to do it.
# 3  
Old 12-10-2009
Quote:
Originally Posted by jstrangfeld
Code:
$ NEWVAR=`echo $(for i in $CARS $FMSA; do echo $i; done |sort |uniq)`
 
$ echo $NEWVAR
a b c d e f g q r s

There are probably easier ways to do it.

Dude I am glad to have A way to do it - thanks!

MM
# 4  
Old 12-10-2009
How about:
Code:
newvar=$(awk '{print $1}' /tmp/file1 /tmp/file2 |sort -u)

Which replaces all the statements.
Last edited by Scrutinizer; 12-10-2009 at 04:53 PM..
# 5  
Old 12-10-2009
Code:
NEW_VAR=`echo $CARS_DATA_LIST $FMSA_DATA_LIST | tr " " "\n" | sort | uniq`

# 6  
Old 12-10-2009
Quote:
Originally Posted by Scrutinizer
How about:
Code:
newvar=$(awk '{print $1}' /tmp/file1 /tmp/file2 |sort -u)

Which replaces all the statements.
Wouldn't that only show the first field?
# 7  
Old 12-10-2009
Yes that is intended. The OP used :
Code:
CARS_DATA_LIST=`cat /tmp/file1 | awk '{print $1}' `
FMSA_DATA_LIST=`cat /tmp/file2 | awk '{print $1}' `

which is using the first fields from these two files. I combine these two in one awk statement, then into a unique sort and subsequently stuff it into a variable.
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