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Shell Programming and Scripting

Removing last two lines

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# 8  
Old 12-08-2009
My new awk script is like this. Am bit confused having two next statements. I read the file first time to find the values X T for which T=0. Then I pass the file again and I have another next statement.

Code:
BEGIN {
    ARGV[ARGC++] = ARGV[ARGC-1]
}

FNR == NR {
    ++j
    $2 || val[j] = $1
    next
}

FNR == 1 {
    print ""
    print "% ( PHASES"
    print "P"
    print "%)"
    print ""
    print "%( SOURCES"
    OFS = ""
    for ( k = 1; k < j; ++k ) {
       if ( val[k] != 0 && val[k] !~ />/ ) { print "(",val[k],",0.0)" }
    }
    OFS = " "
    print "%)"
    print ""
}

/>/ { if ( FNR > 1) { print "%)"; print "%>"; print "" }
      P = 1
      next
    }

P {
    print "%< SOURCE", ++i
    print "%( PHASE 1"
    P = 0
}

!/>/ {
    print $0
}

# 9  
Old 12-08-2009
Would have been nice if you'd posted the code as Danmero asked!

Maybe you can change:

Code:

(FNR > 1)

to
Code:

((NR != FNR) && (FNR > 1))

# 10  
Old 12-08-2009
Had posted the awk scripts, here it is again. I think everything is ok.

Code:
BEGIN {
    ARGV[ARGC++] = ARGV[ARGC-1]
}

FNR == NR {
    ++j
    $2 || val[j] = $1
    next
}

FNR == 1 {
    print ""
    print "%( PHASES"
    print "P"
    print "%)"
    print ""
    print "%( SOURCES"
    OFS = ""
    for ( k = 1; k < j; ++k ) {
       if ( val[k] != 0 && val[k] !~ />/ ) { print "(",val[k],",0.0)" }
    }
    OFS = " "
    print "%)"
    print ""
}

/>/ { if ( FNR > 1) { print "%)"; print "%>"; print "" }
      P = 1
      next
    }

P {
    print "%< SOURCE", ++i
    print "%( PHASE 1"
    P = 0
}

!/>/ {
    print $0
}

# 11  
Old 12-08-2009
Actually, forget the change in my last post, you don't need it.

If your script gives the output you want, then it's OK! Does it?
# 12  
Old 12-08-2009
I agree with you, don't need the last post. Was just trying to think through it and understand how you done it. I understand now. Thanks very much.
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