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Substring based on delimiter, finding last delimiter

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# 1  
Old 12-07-2009
Substring based on delimiter, finding last delimiter
Hi,

I have a string like ABC.123.XYZ-A1-B2-P1-C4. I want to delimit the string based on "-" and then get result as only two strings. One with string till last hyphen and other with value after last hyphen... For this case, it would be something like first string as "ABC.123.XYZ-A1-B2-P1" and secod string as C4.
How can we achieve it? I am using /bin/sh shell.

Thanks for your help.
# 2  
Old 12-07-2009
hello
you can employ perl in your script easily as perl is extremely portable with monstrous regex capabilities. In this I use the greedy quantifier.
Code:
 echo "ABC.123.XYZ-A1-B2-P1-C4 " | perl -wln -e 'print "$1 $2" if /^(.*)\-(.*)$/'
ABC.123.XYZ-A1-B2-P1 C4

regards.
# 3  
Old 12-07-2009
Gaorav
Can you explain this?

if /^(.*)\-(.*)$/
# 4  
Old 12-07-2009
tene..
first I am Gaurav not Gaorav...
well you would have to look at the regex(especially perl's) to understand what they are.
I will explain in short here
. -> a single character except '\n'
* -> 0 or more occurence of the previous character(s)
^ -> start of the string
$ -> end of the string
if you have perl installed then do
Code:
#perldoc perlretut

# 5  
Old 12-07-2009
shell
Code:
INPUT="ABC.123.XYZ-A1-B2-P1-C4"
OUT1=${INPUT%-*}
OUT2=${INPUT##*-}

# 6  
Old 12-07-2009
using sed,

Code:
$ echo "ABC.123.XYZ-A1-B2-P1-C4" | sed 's/\(.*\)-\(.*\)/\1 \2/'

# 7  
Old 12-07-2009
Python
Code:
>>> string="ABC.123.XYZ-A1-B2-P1-C4"
>>> first,last = string.rsplit("-",1)
>>> print first
ABC.123.XYZ-A1-B2-P1
>>> print last
C4
>>>



---------- Post updated at 07:30 AM ---------- Previous update was at 07:30 AM ----------

Python
Code:
>>> string="ABC.123.XYZ-A1-B2-P1-C4"
>>> first,last = string.rsplit("-",1)
>>> print first
ABC.123.XYZ-A1-B2-P1
>>> print last
C4
>>>

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