Shell Programming and Scripting

Hi,

I have read similar questions and I was not able to get a solution, so please help

I have two files:
1-Pattern file contains list of patterns
pattern1
pattern2
pattern3
pattern4

....
pattern#

2-input file in the format

>hdhfshsdfjhpattern1xmbxmbxnmv
bzxnxnbnccm,nvbnmvbnvvn,v,v,v
ncxnmvbnmvbnvvnnv
>vnbnmcbvn,mx,fmf,mnxvm,nv,mnv
nxnvnv,mcn,vn,
>pattern3mmdlskfjkd
nxmnxm,nvmnv


I am trying to remove the line with matching pattern plus the following lines. I have this solution, that will delete the pattern and next line but not the whole record

for keyword in `cat pattern.txt`; do sed -i -e '/'$keyword'./N/d' input.txt; done


Thanks,

do you have blank lines between two paragraph??

No blanks between the paragraphs.


Many Thanks

---------- Post updated at 09:33 AM ---------- Previous update was at 04:20 AM ----------

Sorr for the typo, my command was as follows

for keyword in `cat 3_acc.txt`; do sed -i -e '/'$keyword'/{N;d;}' sample_fas.txt; done

Not good solution, but do the job:

Code:

for keyword in `cat pattern.txt`
do 
   awk 'BEGIN{RS=ORS=">"} !/'"$keyword"'/' input.txt >temp.txt
   mv temp.txt input.txt
done

Many thanks for your reply, it works perfectly.