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Date in Solaris

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# 1  
Old 12-02-2009
Date in Solaris
Hi,

I am working on date operations in perl. using following code, I am getting today date as per my required format.

Code:
my $date1 = `date '+%m/%d/%Y'`;

can I find day+1 date. (ie. If today is 12/01/2009 then I want to edit above code t find 12/02/2009)

---------- Post updated 12-02-09 at 01:58 AM ---------- Previous update was 12-01-09 at 08:28 PM ----------

can anyone please advice
gentleDean
# 2  
Old 12-02-2009
Why do you call an external program for something that Perl can do fine by itself?
Code:
$ cat time.pl
#!/usr/bin/perl

use strict;
use warnings;

my $time     = time;
my @today    = localtime($time);
my @tomorrow = localtime( $time + 24 * 60 * 60 );

printf "   Today: %02d/%02d/%04d\n", $today[4] + 1, $today[3], $today[5] + 1900;
printf "Tommorow: %02d/%02d/%04d\n", $tomorrow[4] + 1, $tomorrow[3],
  $tomorrow[5] + 1900;
$ perl time.pl
   Today: 12/02/2009
Tommorow: 12/03/2009

See the Perl documentation for time, localtime, and gmtime for more information.
Last edited by pludi; 12-02-2009 at 06:36 AM.. Reason: corrected code
# 3  
Old 12-02-2009
Will it give me 12/01/2009 after 11/30/2009. It shouldnt be 11/31/2009.

Also how to take it in a variable?
Last edited by gentleDean; 12-02-2009 at 05:30 AM.. Reason: Asked one more question
gentleDean
# 4  
Old 12-02-2009
  1. Try it. In the above example, change the line
    Code:
    my $time     = time;

    to
    Code:
    my $time     = 1259578800; # 2009-11-30 12:00:00 PM

    and run it again.
  2. perldoc -f sprintf
We won't do all the work for you, you know.
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