Averaging segments and including the name


 
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# 1  
Old 12-01-2009
Averaging segments and including the name

Hello,
I have a awk line that averages rows.

So if my file looks like this:

Code:
Jack  1  1  1  1  1  1
Joe    1  1  1  1  1  1
Jerry  0  0  0  0  0  0
John  1  1  1  0  0  0

The awk line below skips column 1 and then averaged the rows

Code:
awk -F'\t' -v r=3 '{for(i=r+1;i<=NF;i+=r){for(j=0;j<r;j++){sum+=$(i-j)}printf "%s ", sum/r;sum=0}; printf "\n"}'

The end product looks like this
Code:
1  1  
1  1 
0  0
1  0

Basically what I want to do is print the first column as well... (the names)

So the end product will look like this:

Code:
Jack  1  1
Joe    1  1
Jerry  0  0
John  1  0

what modifications do I need to make?
thanksSmilie
# 2  
Old 12-01-2009
I don't fully understand the logic, but.... I think you want this:
Code:
awk -F'\t' -v r=3 '
  {
    for(i=r+1;i<=NF;i+=r){
       printf("%s%c", $1, OFS)
       for(j=0;j<r;j++)
          sum+=$(i-j)
       printf "%s ", sum/r;sum=0
   }
   printf "\n"
 }' myFile

# 3  
Old 12-01-2009
binning

basically I want to bin starting at column 2 (and also print the first column). The bin size can vary , but in this case its 3.

I had some problems with that line, I dont quite understand the change.
# 4  
Old 12-02-2009
Code:
awk -F'\t' -v r=3 '
{
  printf("%s%c", $1, OFS)
  for(i=2;i<=NF; i+=r) {
     for(j=0; j<r;j++)
       sum+=$(i+j)
     printf("%d%c", sum/r, (i+j-1==NF)?ORS:OFS)
     sum=0
  }
}' myFile

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