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Shell Programming and Scripting

Eliminating output?

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# 1  
Old 12-01-2009
Eliminating output?
Hi Folks,

I am writting a shell script for general purpose use....

i have created a function like below:-

Code:
 
largest_file()
{
clear
tput cup 20 30
echo please enter the full directory path where you want to search:-
tput cup 21 30
read lr_choice1
tput cup 22 30
echo please enter the no of files you want to get:-
tput cup 23 30
read lr_choice2
cd $lr_choice1
find $lr_choice1 -type f -print | xargs ls -l | sort -k5,5rn | head -"$lr_choice2" > 
$script_dir/top_$lr_choice2_file_$date_var.txt
tput clear
tput cup 20 0
cat $script_dir/top_$lr_choice2_file_$date_var.txt
tput cup 25 0
echo press hit to continue
read hit
}

I call the function in a interactive shell script for displaying the n largest file in a directory..

Now when i call this function in a switch case programme.....i dont want to show the output generated by the find command .....i just want end results....

like if i call the function it should write only to the file and not stdoutput for operation so that user shouldn't know what happening...

your help is appreciated... Smilie
# 2  
Old 12-01-2009
I haven't tested but this should work:

Code:
find $lr_choice1 -type f -print | xargs ls -l | sort -k5,5rn | head -"$lr_choice2" > 
$script_dir/top_$lr_choice2_file_$date_var.txt 2>/dev/null

Last edited by pludi; 12-01-2009 at 02:17 PM.. Reason: code tags, please...
# 3  
Old 12-01-2009
Code:
find $lr_choice1 -type f -exec ls -s {} \; |sort -nr |head -"$lr_choice2"

# 4  
Old 12-02-2009
excellent that works


cheers!!!
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