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Using awk command for .csv file

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# 8  
Old 12-02-2009
Quote:
Originally Posted by sushmab82
Hi,
I need last record(last row value) of column 16. Suppose column 16 has 2 records(2 rows) I want to grep and store 2nd record of column16 i.e 3 in my input file.
Ok, if you need column 16 only, use:

Code:
awk -F\; '{print $16}' input
cut -d\; -f16 <input

If you need last column 16, use:

Code:
awk -F\; '{print $16}' input |tail -1
cut -d\; -f16 <input |tail -1
awk -F\; 'END {print $16}' input

Last edited by rdcwayx; 12-03-2009 at 01:51 AM..
# 9  
Old 12-02-2009
If you mean to store column 16 of all records in an array use below:-

code:-

Code:
gawk -F";" '{a[16]=a[16]";"$16 ; next}
END{for (i in a) {print i,a[i]} }
' file.txt

SmilieSmilieSmilieSmilie
# 10  
Old 12-03-2009
This is what I exactly wanted, Thanks RDC and ahmad for your useful timely reply.
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