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Taking sed result in a variable

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# 1  
Old 11-25-2009
Taking sed result in a variable
Hi All,

How can i take the following code having three seds into a variable :

Code:
echo "$DateFileFormat" | sed 's/\./\\\\./g' | sed 's/\$/[0-9]+/g' | sed 's/\#/'$job_date'/g'

I want to get the result stored in a script variable

i tried
Code:
var2=`echo "$DateFileFormat" | sed 's/\./\\\\./g' | sed 's/\$/[0-9]+/g' | sed 's/\#/'$job_date'/g'`


but didnt work
# 2  
Old 11-25-2009
Define 'did not work'
Code:
export myvar=""

echo "$DateFileFormat" | sed 's/\./\\\\./g' | sed 's/\$/[0-9]+/g' | sed 's/\#/'$job_date'/g' | read myvar

echo "$myvar"

# 3  
Old 11-25-2009
Hi ,

This is not working

---------- Post updated at 10:43 AM ---------- Previous update was at 10:32 AM ----------

Hi All,

If i do

Code:
echo "$DateFileFormat" | sed 's/\./\\\\./g' | sed 's/\$/[0-9]+/g' | sed 's/\#/'$job_date'/g'

i get the right format in the out put that is

EGZAFU01\\.DOXR\\.UK\\.01\\.25112009\\.S001\\.V1\\.D[0-9]+\\.data\\.txt


but if i use the code which gets the value in a variable that is :

Code:
var2=`echo "$DateFileFormat" | sed 's/\./\\\\./g' | sed 's/\$/[0-9]+/g' | sed 's/\#/'$job_date'/g'`

the var2 variable gets following value :

EGZAFU01\.DOXR\.UK\.01\.25112009\.S001\.V1\.D$\.data\.txt[0-9]+


As you can see the $ has not been replaced with [0-9]+ and the "\\" have changed to '\
# 4  
Old 11-25-2009
first, you can do that in a single sed command, usig the -e flag :
Code:
VAR=`echo "$DateFileFormat" | sed -e 's/\./\\\\./g' -e 's/\$/[0-9]+/g' -e 's/\#/'$job_date'/g'`

Now, your problem comes probably from posix parameter set to on in your shell, type a man sed to see the regex possibilities.
try "--regexp-extended" or "-r", maybe it works.
# 5  
Old 11-25-2009
Code:
var2=$(echo "$DateFileFormat" | sed "s/\./\\\\\\\\./g;s/\\\$/[0-9]+/g;s/\#/$job_date/g")

Code:
$> echo $var2
EGZAFU01\\.DOXR\\.UK\\.01\\.25112009\\.S001\\.V1\\.D[0-9]+\\.data\\.txt




---------- Post updated at 23:25 ---------- Previous update was at 23:16 ----------
ksh/bash:
Code:
var=${DateFileFormat//\./\\\\.}
var=${var//$/[0-9]+}
var=${var//#/$job_date}

Code:
$> echo $var
EGZAFU01\\.DOXR\\.UK\\.01\\.25112009\\.S001\\.V1\\.D[0-9]+\\.data\\.txt

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