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Extracting the strings matching a pattern from a word

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# 1  
Old 11-23-2009
Extracting the strings matching a pattern from a word
Hi All ,

I need to extract the strings that are matching with the pattern :
Code:
CUST.<AnyStringOfAnyLength>.<AnyStringOfAnyLength>

from a file and then write all these string into another file.

e.g. If a file SOURCE contains following lines :

Code:
IF(CUST.ABCD.EFGH==1) THEN
CUST.ABCD.EFGH = CUST.IJKL.MNOP + CUST.QRST.UVWX 
CUST.YZA.BCDE = CUST.ABCD.EFGH -1 
ENDIF

Then I need to extract following strings and write them to some other file DEST.
Code:
CUST.ABCD.EFGH
CUST.IJKL.MNOP
CUST.QRST.UVWX
CUST.YZA.BCDE 
CUST.ABCD.EFGH

Please suggest a solution or approach to meet required stuff.
TIA
# 2  
Old 11-23-2009
Try:
Code:
egrep -o 'CUST\.\w+\.\w+' SOURCE > DEST

# 3  
Old 11-25-2009
Thanks for the reply.

Unfortunately , egrep and grep both are not supporting "-o" option on the unix flavor I am working upon.Any other solution or approach ?
# 4  
Old 11-25-2009
So you don't want to match the if statement? You only show the string CUST.ABCD.EFGH once in your required output

Code:
IF(CUST.ABCD.EFGH==1) THEN

# 5  
Old 11-25-2009
Yes steadyonabix. I need to show the matching string once only, whatever may be the number of times a matching string is repeated.
# 6  
Old 11-25-2009
Try this and let me know if it is what you want: -

Code:
nawk '{
        for ( i = 1; i <= NF; i++ )
                if ( $i ~ /^CUST\..*\..*$/ )
                        printf( "%s\n", $i )
}' infile | sort -u

# 7  
Old 11-25-2009
Code:
my $str="IF(CUST.ABCD.EFGH==1) THEN CUST.ABCD.EFGH = CUST.IJKL.MNOP + CUST.QRST.UVWX CUST.YZA.BCDE = CUST.ABCD.EFGH -1 ENDIF";
my @tmp=$str=~/([A-Z]+\.[A-Z]+\.[A-Z]+)(?!.*THEN)/g;
print join "\n", @tmp;
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