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Shell Programming and Scripting

Extract the letter from string

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# 8  
Old 11-23-2009
bash example
try this :
Code:
#!/bin/bash
read -p "Enter your words : "
for I in $REPLY
do
    let L=${#I}-1
    echo ${I:$L:1}
done

# 9  
Old 11-23-2009
Code:
$ echo "secret1 secret2 serect3" |  awk 'BEGIN {RS=" "; ORS=" "} {key=substr($1,length($1)); print key}'

This should return whatever is in the last space of each string...
# 10  
Old 11-23-2009
Quote:
Originally Posted by mkastin
Code:
$ echo "secret1 secret2 serect3" |  awk 'BEGIN {RS=" "; ORS=" "} {key=substr($1,length($1)); print key}'

This should return whatever is in the last space of each string...
here, the great advantage of awk is that the first index in a string is 1 (0 in bash).Smilie
# 11  
Old 11-23-2009
Code:
echo "secret1 secret2 secret3" | sed 's/\w*\(\w\)/\1/g'



---------- Post updated at 23:01 ---------- Previous update was at 22:43 ----------

Code:
secrets="secret1 secret2 secret3" 
for i in $secrets; do
  echo ${i#${i%?}}
done

# 12  
Old 11-23-2009
Quote:
Originally Posted by Scrutinizer
Code:
echo "secret1 secret2 secret3" | sed 's/\w*\(\w\)/\1/g'

Can you explain the w's for me? Smilie
# 13  
Old 11-23-2009
Hi,

\w matches any "word" character. A "word" character is any letter or digit or the underscore character.
# 14  
Old 11-24-2009
for example,

Enter the names: Test hai hello

I need the last digits of all the inputs..
here " tio " [last digits of Test hai hello]

Hope, you can understand my req. Thanks for your help
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