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Extracting N lines match number X of a pattern

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# 1  
Old 11-20-2009
Extracting N lines match number X of a pattern
Hi All,
as the title says I need to extract N lines after match number X of a pattern.
e.g.
111
xxx
xxx
111
yyy
yyy
111
www
www
111
zzz
zzz

I would like to extract the two lines after the second 111 occurrence.

I tried with grep but I didn't find any options to do that.
Any help?
Thank you,
Sarah
# 2  
Old 11-20-2009
Try:

Code:
sed -n '/111/ { n;N;p; }' filename

or

Code:
awk '/111/ { getline; getline; print; }' filename

or

Code:
grep -A2 111 filename

# 3  
Old 11-20-2009
grep didn't work

Probably I was not clear enough:

I need to extract X lines after the Nth occurrence of a pattern.

The patter cointains '/' character this gave probably problem on sed.

something like

1/1/1/1
qweqw
qweqw
qweqe
1/1/1/1
qewq
qewq
1/1/1/1
qwe
1/1/1/1
1/1/1/1
# 4  
Old 11-20-2009
bash
Code:
cnt=0
pat="111"
num_lines=2
while read -r line
do
    case "$line" in
        $pat) cnt=$(( cnt+1 ))
    esac
    if [ "$cnt" -eq 2 ] ;then
        for((i=1;i<="$num_lines";i++))
        do
            read line
            echo $line
        done
        break
    fi 
done < "file"

# 5  
Old 11-20-2009
Code:
#! /bin/sh
line="$(grep -n '111' inputfile | head -n 2 | tail -n 1 | cut -d: -f1)"
let start=line+1
let end=start+1
sed -n "$start,$end"p inputfile

# 6  
Old 11-20-2009
Quote:
Originally Posted by f_o_555
grep didn't work

Probably I was not clear enough:

I need to extract X lines after the Nth occurrence of a pattern.

The patter cointains '/' character this gave probably problem on sed.

something like

1/1/1/1
qweqw
qweqw
qweqe
1/1/1/1
qewq
qewq
1/1/1/1
qwe
1/1/1/1
1/1/1/1
To get the 2 lines after the 2nd match of the pattern "1/1/1/1":

Code:
awk '/1\/1\/1\/1/ && ++c==2{p=2;next}p-->0' file

# 7  
Old 11-20-2009
thank you, now I have another problem some 0x0C characters in some lines.
In this way the line not read!!!

---------- Post updated at 05:57 AM ---------- Previous update was at 05:41 AM ----------
Quote:
Originally Posted by Franklin52
To get the 2 lines after the 2nd match of the pattern "1/1/1/1":

Code:
awk '/1\/1\/1\/1/ && ++c==2{p=2;next}p-->0' file

we're almost there with awk
it works with numeric values but not with variables, e.g.

Code:
awk '/1\/1\/1\/1/ && ++c==$OCCURRENCE{p=$LINESTOGET;next}p-->0' file
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