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Extracting N lines match number X of a pattern

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# 8  
Old 11-20-2009
You can use the variables this way:

Code:
awk -v occ=$OCCURRENCE -v nlines=$OCCURRENCE '/1\/1\/1\/1/ && ++c==occ{p=nlines;next}p-->0' file

# 9  
Old 11-20-2009
Quote:
Originally Posted by Franklin52
You can use the variables this way:

Code:
awk -v occ=$OCCURRENCE -v nlines=$OCCURRENCE '/1\/1\/1\/1/ && ++c==occ{p=nlines;next}p-->0' file

One more thing, can also the string be a variable in awk?
The string may contain /
so I guess something like

Code:
awk -v occ=$OCCURRENCE -v nlines=$OCCURRENCE '/$STRING/ && ++c==occ{p=nlines;next}p-->0' file

[/QUOTE] ?
Last edited by f_o_555; 11-20-2009 at 09:24 AM..
# 10  
Old 11-20-2009
Quote:
Originally Posted by f_o_555
One more thing, can also the string be a variable in awk?
The string may contain /
Something like:

Code:
awk -v var="1/1/1/1" '$0 ~ var && ++c==2{p=2;next}p-->0' file

# 11  
Old 11-21-2009
Using Perl:

Code:
$
$ cat -n f1
     1  1/1/1/1
     2  abcde
     3  fghij
     4  klmno
     5  1/1/1/1
     6  pqrs
     7  tuvw
     8  1/1/1/1
     9  xyz
    10  1/1/1/1
    11  ABCD
    12  EFGH
    13  1/1/1/1
    14  IJKLMNOP
$
$ # print 1 line after 3rd occurrence of "1/1/1/1"
$ perl -lne 'BEGIN{$O=3; $N=1; $P="1/1/1/1"} if (/$P/ && ++$o==$O){$x=1} elsif ($x && ++$n<=$N){print}' f1
xyz
$
$ # print 2 lines after 4th occurrence of "1/1/1/1"
$ perl -lne 'BEGIN{$O=4; $N=2; $P="1/1/1/1"} if (/$P/ && ++$o==$O){$x=1} elsif ($x && ++$n<=$N){print}' f1
ABCD
EFGH
$
$

tyler_durden
# 12  
Old 11-21-2009
-need to refresh first --
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