Shell Programming and Scripting

In your original code, try adding a space after %s:

Code:

printf ("%s " , $9) >>"filelist.dat"

the space does this to filelist.dat:

abc.csv
(space)def.csv

when i set this file to a variable i get:

echo $files_found:

(space)def.csvbc.csv

Code:

$ cat pablo.sh
awk -F '[ \r]*' '
/^-/ { print $9 }
' x.log > filelist.dat

files_found=$(<filelist.dat)

echo Print without quotes
echo $files_found

echo Print withquotes
echo "$files_found"

$ ./pablo.sh        
Print without quotes
abc.csv def.csv
Print withquotes
abc.csv
def.csv
$

Jean-Pierre.

copied everything you have done in your thread Jean Pierre and i get:

with quotes:

abc.csvdef.csv

I am struggling to understand why it is not doing this. I am usin g KSH

Please, post the output of the following commands :

Code:

$ grep '^-' x.log | od -cx
$ od -cx filelist.dat

Jean-Pierre.

please see below Jean Pierre:

out put from grep '^-' x.log | od -cx:

0000000 - r w x r w x - - - 1 n
2d72 7778 7277 782d 2d2d 2020 2031 206e
0000020 o - u s e r n o - g r o u p
6f2d 7573 6572 2020 6e6f 2d67 726f 7570
0000040 8 3 6 6 6 7 7 S e p 3 0
2020 3833 3636 3637 3720 5365 7020 3330
0000060 1 1 : 5 9 a b c . c s v \r \n
2031 313a 3539 2061 6263 2e63 7376 0d0a
0000100 - r w x r w x - - - 1 n
2d72 7778 7277 782d 2d2d 2020 2031 206e
0000120 o - u s e r n o - g r o u p
6f2d 7573 6572 2020 6e6f 2d67 726f 7570
0000140 5 1 2 O c t 7
2020 2020 2020 3531 3220 4f63 7420 2037
0000160 1 1 : 1 7 d e f . c s v \r \n
2031 313a 3137 2064 6566 2e63 7376 0d0a
0000200


output from od -cx filelist.dat

0000000 a b c . c s v \r d e f . c s v \r
6162 632e 6373 760d 6465 662e 6373 760d
0000020

I don't understand why awk is using \r as the record separator.
Try to force the value of the record separator :

Code:

awk -F '[ \r]*' -v ORS='\n' '
/^-/ { print $9 }
' x.log > filelist.dat

Jean-Pierre.

Please use CODE tags in your posts.