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BASH Varible nesting and user input

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# 1  
Old 11-18-2009
BASH Varible nesting and user input
Well, I think I've managed to take two different issues and conglomerate them into and embarrasing mess.

Code:
 
#!/bin/bash
# Set some variables
dir1=/path/that/isnt/variable/$variabledir/dir/
dir2=/path/that/isnt/variable/$variabledir/important/"$variabledir"-subdirectory/path/
 
echo "Gimme input, a whole lotta input"
echo ""
read variabledir
echo "Your input is: $variabledir"
echo $dir1
echo $dir2
#
exit 0

Why is this not working? Or, why is it working, and just not as expected? Reading throws me a null value for variabledir.

TIA!
# 2  
Old 11-18-2009
Quote:
Originally Posted by karlp
Well, I think I've managed to take two different issues and conglomerate them into and embarrasing mess.

Code:
 
#!/bin/bash
# Set some variables
dir1=/path/that/isnt/variable/$variabledir/dir/
dir2=/path/that/isnt/variable/$variabledir/important/"$variabledir"-subdirectory/path/


$dir1 and $dir2 will contain whatever the value of $variabledir is at the moment of assignment.
Quote:
Code:
echo "Gimme input, a whole lotta input"
echo ""
read variabledir
echo "Your input is: $variabledir"
echo $dir1
echo $dir2
#
exit 0

Why is this not working? Or, why is it working, and just not as expected? Reading throws me a null value for variabledir.
Code:
 
#!/bin/bash
# Set some variables
dir1=/path/that/isnt/variable/\$variabledir/dir/
dir2=/path/that/isnt/variable/\$variabledir/important/\$variabledir-subdirectory/path/
 
echo "Gimme input, a whole lotta input"
echo ""
read variabledir
echo "Your input is: $variabledir"
eval "echo $dir1;echo $dir2"
#
exit 0

# 3  
Old 11-18-2009
So, thanks, two questions...

1: The slashes prior to the dollar sign in dir1 and dir2, are those there for a reason?
2: Will removing the quotes from dir2's use of variabledir cause the -subdirectory to be appended, or would it be treated as a full and new variable with a dash in the name?

EDIT: 2 is not an issue, and I'm not sure why the slashes helped, but they did. Thanks a bunch!
Last edited by karlp; 11-18-2009 at 02:28 PM..
# 4  
Old 11-18-2009
Quote:
Originally Posted by karlp
So, thanks, two questions...

1: The slashes prior to the dollar sign in dir1 and dir2, are those there for a reason?

The slashes preserve the dollar signs as literal dollar signs.
Quote:
2: Will removing the quotes from dir2's use of variabledir cause the -subdirectory to be appended, or would it be treated as a full and new variable with a dash in the name?

The quotes don't do anything, so removing them doesn't affect anything.

(Quotes are only necessary in a variable assignment to preserve literal whitespace.)
# 5  
Old 11-18-2009
Thanks for the quick reply...

This is in fact a piece of a script for processing files associated with a particular application, and part of the script uses unzip to process files according to these variables.

Code:
unzip -n $dir2/$variabledir.zip

And I keep getting half of the string.

Code:
unzip:  cannot find or open /path/that/isnt/variable/$variabledir/dir/\$variabledir-subdirectory/path/$variabledir.zip

# 6  
Old 11-18-2009

Code:
eval "dir1=$dir1"
eval "dir2=$dir2"

# 7  
Old 11-18-2009
Code:
dir1=/path/that/isnt/variable/${variabledir}/dir/
dir2=/path/that/isnt/variable/$variabledir/important/${variabledir}-subdirectory/path/
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