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Shell Programming and Scripting

Spaces in Lines for Variables

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Old 11-18-2009
Output
rm -f '"vol13/grch76/200013935/Characterizations of Plastics/Optical profiles/3 mil Al foil.tif.20091111170111-2072-1292-0.ark_tagging"'

This is the output from the log file. It looks like there is a single quote and a double quote around the front and back of this line. The rm -r command doesn't alert as to whether it was successful.

---------- Post updated at 02:18 PM ---------- Previous update was at 01:37 PM ----------

I figured it out.

the variables have to be quoted as a whole such as:
Code:
#!/bin/sh

while read -r line
do
  FULLFILENAME="`basename "$line"`
  SHORTFILENAME="`echo "$FULLFILENAME" |cut -f 1,2 -d .`"
  FULLPATHNAME="`dirname "$line"`
  echo "$FULLFILENAME"
  echo "$SHORTFILENAME"
  echo "$FULLPATHNAME"
  echo "rm "$FULLPATHNAME"/"$FULLFILENAME""  >> fixit.log 2>&1
  echo "rm "$FULLPATHNAME"/"$SHORTFILENAME"" >> fixit.log 2>&1
  #rm -f "$FULLPATHNAME"/"$FULLFILENAME" >> fixit.log @>&1
  #rm -f "$FULLPATHNAME"/"$SHORTFILENAME" >> fixit.log 2>&1
  #echo "cp -p "$FULLPATHNAME"/.snapshot/nightly.8/"$SHORTFILENAME" "$FULLPATHNAME"" >> fixit.log 2>&1
  #cp -p "$FULLPATHNAME"/.snapshot/nightly.8/"$SHORTFILENAME" "$FULLPATHNAME" >> fixit.log 2>&1
done < donw.out

I didn't have the double quotes before the back tick of the variable definition.
Thanks for the responses.
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